"A Sepak Takraw Ball Is Hit Vertically Upward By A Player. What Is Its Acceleration After 1 Second?, A. 0, B. 1 M/S2, C. 9.8 M/S2, D. -9.8m/S2, "

"A sepak takraw ball is hit vertically upward by a player. What is its acceleration after 1 second?

a. 0
b. 1 m/s2
c. 9.8 m/s2
d. -9.8m/s2
"

 

Answer:

The acceleration of the sepak takraw ball after 1 second would be D, -9.8\frac{m}{s^2}.

Explanation:

The sepak takraw ball is placed into a vertical projectice scenario. In other words, the object travels only at x-axis. Assuming that the player is from Earth, anything sorrounding him would be in an acceleration of 9.8\frac{m}{s^2} towards the center of the planet. Since the ball traveled upward, the acceleration would be negative, indicating its acceleration magnitude and its direction in relation to gravity (opposing direction).

CODE:

9.22.4.1.


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